how is the acceleration due to gravity at all points inside a spherical shell of uniform density zero?
Answer Dear naina, Gravity does cancel out for all points inside a hollow spherical shell. That is, assume there is no air inside a soccer ball, the gravity from the soccer ball on an ant floating anywhere inside the ball will sum to zero. This can be shown by adapting the integral form of Gauss’s Law replacing the magnetic field with the gravitational field. If you are not yet familiar with vector calculus in order to use Gauss’s Law directly, then you can simply think about it this way. In the exact middle of the hollow shell, there will be a gravitational pull from every point on the shell, but each point will have a different direction. In fact, for every point with a gravitational pull in one direction, there is a point on the exact opposite side of the ball with the same amount of pull but in the opposite direction. As you move from the middle to some other point inside the ball, you move closer to one edge of the ball than the other, and thus the forces from one side become stro
