Can You Use The Discriminant To Determine The Number Of Real Solutions Of The Equation?
Rearrange the equation so that it becomes: 5zsquare – 2z + 7 The discriminant is supposed to be = bsquare – 4ac So the discriminant for this one becomes= (-2)square – 4(5)(7) = 4 – 140 = -136 Now the answer is negative which means it is less than zero, and this implies that there are no real roots.
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