Why doesn nickel form low spin octahedral complexes?
may be my explanation is useful to u.Ni have outer most electronic configuration 4s2 3d8.the hybradisation for octahedral complex is sp2d3.for low spin octahedral complexes the hybradisation is d2sp3.there is two cases for nickle for forming octahedral complexes. first case: when the ligand is weak then there is no pairing up of electrons in the d-orbital hence there is no d-orbital for acquiring the d2sp3 hybradisation.hence low spin complexes are not formed. second case:when the ligand is strong there is a pairing up of electrons.but there is only one vacant d-orbital available for hybradisation.so here also d2sp3 hybradisation is not formed.hence low spin octahedral complex is not formed. thus we can concluded that nickel doesn’t forms low sin octahedral complexes.
