When electricity flow through a wire then if I cut this wire , why no electron jump from wire ?
The air has a high resistance, meaning that the charge carries are less likely to get through. If the electromotive force (terminal voltage) is large enough it will jump, due to the electrons being able to ionise the air, due to the larger amount of energy they have. One could use this with momentum to explain it: K.e = 1/2 m v(squared) emf is proportional to K.e. of electrons Or use these: nAVE=I n=volume density of charge carriers A=cross-sectional area of wire V=mean drift of electrons through the wire E=the charge on the electron I= Current Then applying V=IR (Voltage = current x time) you eventually get the fact that velocity and mass of electrons are somehow linked if you could devise some kind of complicated equation… so if the voltage was large enough, then the electron will jump.
