What would be the difference (in decibels) of an aircraft flying at 100 feet over a home, compared to one flying at 500 feet over a home? What equation is used to determine the change in decibels?
A. 13.979 dB. The change in decibels (dB) is determined by the following equation: 20 times the logarithm base 10 of the ratio of those two distances. In the question presented, the answer is determined as 20 times the log of 100 over 500 or 20 * log (100 / 500) = -13.9794001. For a rough linear estimate, sound in decibels (dB) from a point source changes about 6 dB for each doubling of distance. For a specific case explanation CLICK HERE.
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