What will be the effects of accepting a 1:1000 slope versus a perfectly flat lawn in term of drainage and ball deviations?
Volume of wedge = integral from 0..62 of 1/2* 72*(x*((0.136-0.072)/62)+0.072).dx = 232.128 m3 Soil Calculations I calculate that the wedge of soil described by the four corners’ elevations you give approximates to a cubic volume of 232 m3 un-bulked soil (I took the 0mm-0mm edge to be the 62m one). As a sanity check if all this soil was re-spread to a uniform depth over the 72 x 62m area it would be 52mm high – which would be your cut and fill depth for moving the minimum amount of soil, which I guess is half 232 m3 = 116m3. Provided that you are happy for the final surface to be 52mm above your datum (0mm), then the work can be reduced: you would not want to rotary hoe any land lying at or around the 0mm level as 50mm of soil will be added on top, and you move the minimum amount of soil. It does presume that at the high points there is a sufficient depth of topsoil remaining once you have skimmed off 84mm (136-52mm). Slopes My enthusiasm for doing a further integration to work out the
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