What is the specific heat capacity of this metal?
Essentially, the the heat energy gained by the water= the heat energy lost by the metal Heat energy gained by the water, Q= mcΔT where m is the mass of the water, c is the specific heat capacity of water and ΔT is the change in temperature of the water. Q= 15.0 x 4.186 x (50.5-22) = 1789.515 J Heat energy gained by the piece of metal, Q= mcΔT where m is the mass of the metal, c is the specific heat capacity of the metal and ΔT is the change in temperature of the metal which is 28.5°C Rearranging the formula, we get c= Q/mΔT = 1789.515/(80)(28.5) = 0.784875J/kg/°C(answer) I hope this helps!
