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What is the oxidation states to the elements in Na2S2O3?

April 26, 2017Chemistry elements Mathematics oxidation

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What is the oxidation states to the elements in Na2S2O3?

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You have to look at the groups. Na is in group 1 so the oxidation number is +1. Oxygen is always -2. There are 2 Nas with +1 oxidation, so that’s +2 3 O, so that’s -6 For a balanced charge, S needs to be +4, there are 2 so the oxidation is +2. The answer is 3. For the second question, balance the equation. Since there are 5 C’s on the left, there must be 5 C’s on the right. C5H12 + O2 -> 5CO2 + H2O To have 12 H on the right, there needs to be a coefficient of 6 on the water, C5H12 + O2 -> 5CO2 + 6H2O Now for the Oxygen, there are 16 Os on the right and 2 on the left, so the left needs a coefficient of 8. The final balanced eqn is: C5H12 + 8O2 -> 5CO2 + 6H2O. Add the coefficients: 1 + 8 + 5 + 6 = 20 The answer is 3.