What is the moment of inertia of a 8.0 Kg 10. cm radius sphere about its center?
Just the same as problem #1, you can solve this problem by looking up the equation for the moment of inertia for a sphere. This formula is: I=2/5mr I= (2/5) * (8kg) * (.1) I= .032Kgm (Table of contents) 3. What is the torque when you exert a force of 52 N on a 56 cm breaker bar? In this problem, you are given the force (52N) and the radius (.56 meters). By using the equation: t = Fr, you can arrive at your answer. Just plug in the numbers: t = (52N) * (.56m) And the final answer is: t = 29.12Nm (Table of contents) 4. What force should you exert on a 14 cm long wrench to get a torque of 42 Nm? This problem is similar to #4 in that you must use the equation t = Fr, however, you are given different values. In this problem, you are given the final torque value (42 Nm), and the radius (.14 meters). Therefore, you must reshape the formula to solve for the force: t / r = F Then, by plugging in the numbers: (42Nm)/(.14m) = Force You arrive at your answer of: 300N (Table of contents) 5. . If yo
