What is the maximum speed of this banked curve?
Question What is the maximum speed of this banked curve? Sometimes roads have a “reversed” banking angle. That is, the road is tilted “away” from the center of curvature of the road. If the coefficient of static friction between the tires and the road is μs = 0.6, the radius of curvature is 24 m, and the banking angle is 15°, what is the maximum speed at which a car can safely navigate such a turn When the car is at rest on the banked curve, the component of the weight of the car that is perpendicular to the incline causes friction. The perpendicular force that the car exerts on the road = m*g*cos 15°. Since the car is at rest, the road is exerting an equal and opposite force on the car = m*g*cos 15°. As the velocity of the car increases, the perpendicular force that car exerts on the road decreases. This decrease is caused by a force that is equal and opposite to the centripetal force = mv^2/r. The total perpendicular force = m*g*cos 15° – mv^2/r The friction force is holding the car
