What is the equation of a perpendicular line?
The general equation for a straight line is y = mx + a where m is the gradient For the perpendicular line, the equation is… y = (-1/m)x + b You are right, the gradient of the perp line is -1/2 So its equation is… y = (-1/2)x + b When it passes thru the point (1,6), it becomes… 6 = (-1/2)*1 + b so, b = 6 + 1/2 = 6.5 And the equation becomes… y = (1/2)x + 6.5 Or multiplying both sides by 2…