What happens when an amp is bridged?
Basically, one channel’s signal is inverted, and then the two channels are combined to form one channel with twice the voltage of either of the original channels. Ohm’s Law for Alternating Current states that I = V/Z where I is current, V is voltage, and Z is impedance. We also know that P = IV, where P is power. If we use Ohm’s Law and substitute into the power equation, we get P = V(V/Z), which can be rewritten as P = (V^2)/Z. Therefore, power is the square of voltage divided by impedance. Now, why do we care about all that? Because it explains precisely what happens when an amp is bridged. I’ll give a practical example and explain the theoretical basis of that example. Imagine you have a two-channel amp that puts out 50 watts into each channel when driven into a load of 4 ohms per channel. Since we know P and Z, we can plug these numbers back into our power equation and find V. 50 = V^2/4 -> V = sqrt(200). So, we’re seeing a voltage of 14.1 volts across each channel. Now, imagine we
