What happens when a Teledyne sensor such as B1, B2, B3 or C3 is exposed to high percentage levels of CO2?
1. CO2 will enter the sensor and react with KOH electrolyte to form a carbonate ion. The electrolyte layer between the sensing membrane and the cathode will change pH due to the neutralization of KOH by CO2. Then, a transition response of the sensor will be observed if the CO2 is very high, such as 100% CO2. Most likely, the sensor will go negative and recover. 2. When high levels of CO2 continuously enter the cell, lead carbonate will be formed due to the increase of carbonate ion. Lead carbonate will first deposit over the cathode surface and initially cause the sensor to have a high offset. More importantly, as the coating over the cathode becomes heavier, the sensor output starts to drop. 3. As the lead carbonate continuously forms over the cathode surface, the sensor will lose span due to the coverage of lead carbonate over the cathode surface and the increased thickness of the electrolyte layer between cathode and sensing membrane. 4. As the CO2 continuously enters the cell, it w
Related Questions
- How can we assign the band B1, B2 and B3 of XS to the Red Green Blue colour so that the natural green colour can be reproduced?
- What happens when a Teledyne sensor such as B1, B2, B3 or C3 is exposed to high percentage levels of CO2?
- What Division Level can Leviathan be made to work to, e.g., B1, B2, B3?