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What are the tradeoffs between source power, source-to-detector distance and exposure time?

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What are the tradeoffs between source power, source-to-detector distance and exposure time?

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The x-ray flux follows an inverse square law: doubling the source-to-detector distance reduces the flux per unit area by a factor of four. This can be compensated by increasing the source current or the exposure time. Detector signal also increases with x-ray energy, but using too high a kVp setting can reduce image contrast.

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