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The complex [Fe(C2O4)3]3– has one unpaired electron. What is the electron configuration of this complex?

April 26, 2017Chemistry complex electron Mathematics unpaired

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The complex [Fe(C2O4)3]3– has one unpaired electron. What is the electron configuration of this complex?

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[Fe(C2O4)3]3– The charge on the metal ion is Fe3+ with a dn configuration of d5. If the complex was high spin then it would have an electronic configuration of t2g3 eg2, however this would lead to 5 unpaired electrons. So, we can deduce that the complex is low spin as it has only one unpaired electron, therefore the electron configuration of [Fe(C2O4)3]3– with one unpaired electron is: t2g5 eg0. So the answer is B. Hope that helps.