than the current entering the first resistor?
The secoind potential will be lower only if the second resistor has a higher value than the first. If both resistors are the same the potentials will be the same across each of them. The formula for calcuating potentials across 2 resistors in series is V(1) = (R(1) X V(source)) / (R(1) + R(2)) and so on for the next resistor. Current travelling through resistors in series is the same regardless of where you measure it. This is because the resistors add up their total resistance and limits the current to the same value thoughout the circuit. Charge piles up on the front of the first resistor and then trickles through it to pile up in front of the second resistor, the values of the resistors determine how much current is moving through the whole circuit. If you have a circuit where the second resistor is less than the first, current can more easily travel through it thereby reducing the amount of charge that piles up on its front. This charge will nevertheless still reduce the potential
