Suppose that a 2.0 kg ball is thrown from the top of a building, which is 125 meters high, with a velocity of 42.0 m/sec at an angle of 35o above the horizontal. What will be the velocity of the ball just as it reaches the ground?
• There are no unaccounted forces here so the total energy at the beginning must be equal to the total energy at the end. • At the beginning there are two types of energy present. Gravitational potential energy [GPE] because the ball is at the top of a building and kinetic energy [KE] because the ball is moving since it was thrown. • At the end the only energy remaining is kinetic because the height at the end is zero since the ball strikes the ground. • If you make these two energies equal you get that KE + GPE at the beginning is equal to just KE at the end. Just make them equal and solve for velocity final!
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