In todays charged sphere example problem, was linear in inside the surface. Why doesn change with respect to outside the sphere?
Related Questions
- In todays charged sphere example problem, was linear in inside the surface. Why doesn change with respect to outside the sphere?
- In todays charged sphere example problem, why didn we make a Gaussian surface for part a, but we did for part c?
- In todays charged sphere example problem, why was the potential on the surface of the charged sphere zero?
