Important Notice: Our web hosting provider recently started charging us for additional visits, which was unexpected. In response, we're seeking donations. Depending on the situation, we may explore different monetization options for our Community and Expert Contributors. It's crucial to provide more returns for their expertise and offer more Expert Validated Answers or AI Validated Answers. Learn more about our hosting issue here.

How would you prepare two liters of a 1.35 M lithium nitrate stock solution?

0
Posted

How would you prepare two liters of a 1.35 M lithium nitrate stock solution?

0

1.35 M literally means 1.35 moles of lithium nitrate dissolved in 1 liter of solvent. So to make two liters of 1.35M solution i would measure out 2.70(=1.35*2) moles of lithium nitrate and put it in 2 liters of solvent. then take 2.70 moles * ( molecular weight of lithium nitrate / 1 mole) to find how many grams that is.

Related Questions

What is your question?

*Sadly, we had to bring back ads too. Hopefully more targeted.

Experts123