How would you prepare two liters of a 1.35 M lithium nitrate stock solution?
1.35 M literally means 1.35 moles of lithium nitrate dissolved in 1 liter of solvent. So to make two liters of 1.35M solution i would measure out 2.70(=1.35*2) moles of lithium nitrate and put it in 2 liters of solvent. then take 2.70 moles * ( molecular weight of lithium nitrate / 1 mole) to find how many grams that is.