How to solve for an Angle in a Parallelogram?
I can give you a start: Since the angle at T is 100, the four angles of the parallelogram are 100, 80, 100, 80 The line HS bisects one of the 80 angels, so its angle of THS is 40. So now we know all the angles except the one you want. The shape HSAT has four angles and I believe these should add up to 360.