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In calculus terms, the volume is the integral over the height of volume = integral over 0 to h of (y/h)^2*(base area)(dy) = (1/(3*h^2))(base area)(h^3) = (1/3)*h*(base area) (For those paying attention, this is actually the computation of the volume of an inverted pyramid, one whose apex is found at y=0, and whose base is found at y=h.
