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How sensitive does a meter have to be to sense voltage in an induced current?

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How sensitive does a meter have to be to sense voltage in an induced current?

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There is a formula to calculate the current induced in the wire but it depends on the strength of the bar magnet, the rate of change of the magnetic flux threaded through the current loop, and the resistance of the circuit. The faster you can pass the bar magnet through the loop, the stronger the current. If you have a multimeter, you might test the multimeter with a simpler circuit by hooking it up a battery and a light and seeing if you can measure current flow through the multimeter. To get a rough idea of the voltage and current produced by magnetic induction, suppose your bar magnet has a 1 Tesla magnetic field strength, and that the area of the current loop is 100 cm2 (0.01 m2). When the bar magnet is in the loop the magnetic flux is the product of the field strength and the area. Let’s suppose that the flux goes from zero to 1 Tesla x 100 cm2 in 1 second. If we use the meter-kilometer-second system of units, then the voltage would be about E = 1 T x 0.01 m2/1 s = 0.01 Volts For

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There is a formula to calculate the current induced in the wire but it depends on the strength of the bar magnet, the rate of change of the magnetic flux threaded through the current loop, and the resistance of the circuit. The faster you can pass the bar magnet through the loop, the stronger the current. If you have a multimeter, you might test the multimeter with a simpler circuit by hooking it up a battery and a light and seeing if you can measure current flow through the multimeter. To get a rough idea of the voltage and current produced by magnetic induction, suppose your bar magnet has a 1 Tesla magnetic field strength, and that the area of the current loop is 100 cm2 (0.01 m2). When the bar magnet is in the loop the magnetic flux is the product of the field strength and the area. Let’s suppose that the flux goes from zero to 1 Tesla x 100 cm2 in 1 second. If we use the meter-kilometer-second system of units, then the voltage would be about E = 1 T x 0.01 m^2/1 s = 0.01 Volts For

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