How much time does it take for a convoy to complete in general?
A25.2: MAXSTART + (N-1) + (NUM_IN_CONVOY -1) where MAXSTART is the maximum startup penalty time of all the instructions in the same convoy assuming that the first vector element is computed during the startup penalty; NUM_IN_CONVOY is the number is instructions in the CONVOY; N is the length of the vector. Q25.3: I am having trouble understanding how addresses are assigned to the memory banks that you went over in lecture 25. I have even watched that section of the tape again and I still didn’t understand. There are 8 banks and 8 addresses per bank, so each “row” has 64 addresses. What this looks like to me is the following: 0 1 2 3 4 5 6 7 address: 0 8 16 24 32 40 48 56 64 72 80 88 96 104 112 120 128 136 144 152 160 168 176 184 192 200 208 216 224 232 240 248 I think this is pretty much the same thing as what is shown in the table on page 10 of lecture 25. The cycle column has me completely confused. I don’t understand how you can access the addresses of the same row in the same cycle
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- How much time does it take for a convoy to complete in general?
