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How many moles of Al(NO3)3 if the mass is 231 g?

April 26, 2017AL Chemistry mass Mathematics moles No3

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How many moles of Al(NO3)3 if the mass is 231 g?

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Simply set it up using a conversion factor. 231 g Al(NO3)3 x (1 mol Al(NO3)3 / 213 g Al(NO3)3) = 1.08 mol Al(NO3)3 The conversion factor is a ratio equal to 1. 1 mol of a compound is equal to the molar mass of that compound. set up the conversion factor to cancel out the units you don’t want and leave the units you do. In this case we cancel out grams and leave moles.