How many electrons can be found with principal quantum number n=4 in a suitably heavy atom?
maximum number of electrons in n’th shell = 2 X n^2 in this case n = 4 so maximum number of electrons = 2 X 4^2 = 2 X 16 = 32 so answer is d) some other formula like this are : number of subshells in n’th shell = n number of orbitals in a subshell = 2 X l + 1 (where l is azimuthal quantum number) maximum number of electrons in a subshell = 2 X (2 X l + 1) number of orbitals in n’th shell = n^2
