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How is inelastic scattering more significant than the elastic, for heavy nuclides?

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How is inelastic scattering more significant than the elastic, for heavy nuclides?

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For heavy nuclides, the energy loss in an elastic collision is much smaller than in an inelastic collision. As said earlier, elastic collision results in kinetic energy sharing. A neutron, in an elastic collision with a heavy nucleus, rebounds almost with its initial energy giving very little energy to the nucleus. But, in an inelastic collision a substantial part of neutron energy is used in leaving the nucleus in an excited state.

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