How electric field intensity inside the hemispherical shell can be found?
The use of Gauss’ law to examine the electric field of a charged sphere shows that the electric field environment outside the sphere is identical to that of a point charge. Therefore the potential is the same as that of a point charge: The electric field inside a conducting sphere is zero, so the potential remains constant at the value it reaches at the surface: The electric field must be zero because it is that equilibrium inside the sphere. E=0 The electric field in the metal of the sphere is equal to charge q at the origin. Outside, the electric field is E=(q)/(4)(pi)(Eo)(r^2). the electric field outside is uniformly spread along the surface. The charge on the inner metal surface would be opposite or negative to the charge q. Therefore, for any point inside the shell (or within the conducting material of the shell), the potential is the same as the outside surface. This includes the potential at the center of the shell.
