How do you write a quadratic equation in standard form?
I happened to answer a question about what were we doing tonight and well happened to see you were doing math homework, so I checked your profile and saw you’d posted a question. So here is how its done: f(x) = 3x² + 10x + 4 Group the first two terms: f(x) = (3x² + 10x) + 4 Now factor out the 3 from the first two terms: f(x) = 3(x² + (10/3)x) + 4 Now divide the coefficient in front of the x by 2, square it and then add and subtract inside of the brackets: f(x) = 3(x² + (10/3)x + (5/3)² – (5/3)²) + 4; notice that (10/3) divided by 2 is 10/6 = 5/3 Now we have the -(5/3)² inside the brackets but we want to kick that outside, so we multiply it by the leading coefficient we factored out in the beginning, in this case it is 3: f(x) = 3(x² + (10/3)x + (5/3)²) – 3(5/3)² + 4 Now do a bit of simplifying: f(x) = 3(x² + (10/3)x + (5/3)²) – 13/3 Now notice that we have a perfect square trinomial in the brackets. That is a polynomial of the form (a + b)² = a² + 2ab + b². Therefore, it all becomes: f
