How Do You Solve Calculus Optimization Problems?
Optimization allows you to find the maximum or minimum of any problem. This process requires the use of calculus and may be difficult at times. The optimizing process allows you to solve problems such as the volume of three dimensional objects and the amount of certain materials to use in order to lower production costs. You can solve these problems in two dimensions. Set your variables accordingly and write an equation. Make sure to minimize your variables to just two that relate to one another. Example: 2y = 8x^2+12x Isolate one of the variables (usually the one that goes on the Y axis): y = 4x^2+6x Set the derivative of the equation to 0: f'(y) = 8x+6 0 = 8x+6 Solve for the remaining variable: x = -(3/4) Plug that solution back into the original equation to find the solution for the remaining variables. Graph your original equation and plot your findings.
