How do you get the numbers 1-100 only using 1 2 3 4?
“2^(3!) what does this mean and i cant use it the only signs i can us are + – * / ! ( ) and squared cubed and quadrupled” I assumed that when you said, “if you square cube or 4it them that counts as that number” that meant you could use any powers, so long as you lose the number for that power. So for 2^(3!), that’s effectively 2^6 = 64. If you can’t do that then a lot of the higher numbers are lost; 56, 68, 69, possibly 70, 87, 88 and 89. How do you feel about double factorials? I used 3!! in 58, 90 and 91. What’s the word on KevinMs method of sticking numbers together? I like your function method Kevin, but I don’t think it’ll be allowed: f(x) = (4 – 3)x + 1 f(2) = 3 f(f(2)) = 4 f(f(f(2))) = 5 etc. Only missing 6 with the operations explicitly allowed, I’ll edit them in as I find them: 1 = (4 – 3) * (2 – 1) 2 = 4 – 3 + 2 – 1 3 = (4 – 1) * (3 – 2) 4 = 4 + 3 – 2 – 1 5 = (4 + 1) * (3 – 2) 6 = 4 + 3 – 2 + 1 7 = (4 + 3) * (2 – 1) 8 = (4 – 2) * (3 + 1) 9 = 3 * 2 + 4 – 1 10 = 4 + 3 + 2 + 1
