How do you find the smallest angle in a right angled triangle?
Okay so I was asked to: Sketch a triangle whose side lengths are 6cm, 13cm and 14 cm. Easy peasy. Draw a 13 cm horizontal line, AB. At the right end of the 13 cm line, draw a 6 cm vertical line, BC. Line BC is perpendicular to line AB at Point B. (The angle at B = 90°). Draw the line, AC, which is the hypotenuse of triangle ABC. The angle at Point A is the smallest angle, because it is opposite the smallest side, 6 cm. Use one of the trigonometric ratios to calculate the size of the smallest angle in your triangle.” BC / AC = sine of angle BAC.
