How Do You Calculate Combustion Of Pentane?
Pentane is a saturated hydrocarbon (alkane) and has the chemical formula C5H12. It exists in the liquid state under standard conditions (pressure of 1 bar and 25 degrees Celsius). The chemical reaction between pentane and oxygen results in combustion (burning): C5H12 + 8O2 = 5CO2 + 6H2O. The combustion is always accompanied by heat release. The combustion can be calculated from the enthalpies of formation (denoted as “dH”) of the reagents in the reaction. Obtain the enthalpy of formation for all components of the combustion reaction (see Resources). Note that enthalpies of formation of elements (e.g., oxygen) at the standard conditions are equal to zero. dH(C5H10) = -173.5 kJ/mol dH(O2) = 0 kJ/mol dH(CO2(g)) = -393.5 kJ/mol dH(H2O(l)) = -285.8 kJ/mol Sum up the enthalpies of formation of pentane (C5H12) and O2 (initial reagents), multiplying each value by the corresponding reaction coefficient: dH(initial) = -173.5 kJ/mol + 8 x 0 = -173.5 kJ/mol Sum up the enthalpies of formation of CO
