How did they get the answer for enthalpy change for Ammonia?
Ammonia is made industrially from its elements by the following reaction Nv2(g) + 3Hv2(g) = 2NHv3(g) below is the Molar bond enthalpy for the reaction above Bond ——————————-Molar Bond Enthalpy/kM mol^-1 N-H ———————————391 H-H ———————————436 N(3 bonds)N ———————945 Use the information from the molar bond enthalpies given above to show the overall enthalpy change for the reaction is -93kJ mol^-1
