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How can you calculate the relative abundance of two isotopes when given the atomic masses of both isotopes and also the average atomic mass for the element?

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How can you calculate the relative abundance of two isotopes when given the atomic masses of both isotopes and also the average atomic mass for the element?

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Igloo says The conventional method is to use algebra. Lets take an example. Copper consists mainly of two isotopes, 63Cu and 65Cu, and its (average) atomic mass is 63.55 (to 2 d.p.) Lets assume next that the percentage abundance of 63Cu is x This means that the percentage abundance of 65Cu will be 100-x Given 100 random copper atoms, x will each have a mass of 63 [total mass = 63x] And 100-x will have a mass of 65 [total mass = (100-x) x 65 = 6500-65x] So the total mass of 100 atoms = 63x + 650065x = 65002x This means that the average mass = (65002x) / 100 But we are told in the question that average mass = 63.55 Therefore (6500-2x) / 100 = 63.55 So 65002x = 6355 Hence 2x = 6500-6355 = 145 And x = 72.5 So, in a typical sample of copper 72.5% of the atoms are 63Cu and 27.5% are 65Cu. Another (shorter) method is to use a number scale and intuition, but perhaps you are safer with algebra! Risk assessment Before attempting any practical work based on the advice and suggestions on this webs

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