How can one find the acceleration and tension in a Double pulley system?
This is complicated. There will be needs for illustrations. For every section of rope, you will have to pull the rope that much more to get the load moved the same distance. I will now show the math for a simple pulley system; If you have a pulley system that is like the second source half way down where there is a large mass M, and a small mass m, and tension in the rope T, then the following is the way find acceleration; a=g(M-m)/(M+m) If h is the distance the blocks are moved, the velocity is found from the allowing; v=(2gh(M-m)/(M+m))^0.5 Go to the third source, three illustrations down on the page. The sum of the tension in all three sections equals the external tension. Int this case there are 3 sections of rope and so the tension in the rope is 50N. This means that although the load is 150 N they only have to pull 50 N. A double pully system is esentialy like this. Just picture the pully attached to the load. Check out the illustrations listed in the illustrations below the thir
