How can I calculate the final operating conditions (current, speed, etc.) for a motor+gearhead combination given the torque load at the output shaft of the gearhead?
To give you a generalized example, assume that the motor+gearhead combination M2232U12GS000+M22P24YS000 24:1 is being used with 12 Volts applied to the motor terminals, and that a torque of 10 oz-in is desired at the output shaft of the gearhead. Gearhead M22P24YS000 with a 24:1 gear ratio has a data sheet efficiency value of 70%. This means that 30% of the power developed by the motor will be lost in the gearhead. The simplest method of accounting for gearhead losses is to increase the torque requirement by the appropriate amount and make the calculations as if the gearhead were 100% efficient. In this case, we increase the torque requirement at the gearhead output by 30% resulting in a torque (for calculation purposes) of 13 oz-in. Total torque = 10 oz-in x 1.3 = 13 oz-in. The torque reflected back to the motor is then simply the total torque divided by the gear ratio: Motor torque = 13 oz-in / 24 = .542 oz-in. The motor torque constant is the proportionality constant which defines t
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