Give two ways of converting a two input NAND gate to an inverter?
Ans: (a) Short the 2 inputs of the NAND gate and apply the single input to it.(b) Connect the output to one of the input and the other to the input signal. 12) Convert D-FF into divide by 2.What is the max clock frequency the circuit can handle, given the following information?T_setup= 6nS T_hold = 2nS T_propagation = 10nS Ans:Circuit: Connect Qbar to D and apply the clk at clk of DFF and take the O/P at Q. It gives freq/2. Max. Freq of operation: 1/ (propagation delay+setup time) = 1/16ns = 62.