Find the angle hat the wheel will be in static equilibrium?
I don’t get 28 degrees, but here’s my argument: Let the plane slope downward to the right. Take torques about the center of the wheel. Then the plane exerts a clockwise torque equal to Mgr sin 20. This must be balanced by a CCW torque exerted by the point mass, which exerts a downward force mg. Call the angle between the radius to the point mass and the downward vertical a. Then the torque is the tangential component mgr sin a. So m sin a = M sin 20; 0.95 sin a = 1.5 sin 20; a = 32.
