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Find critical points for y=1+(7/x)-(3/x^2)

Calculuscalculus
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Samreen Taj Posted

Find critical points for y=1+(7/x)-(3/x^2)

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Saad Khan

To find critical points first derivative should be found of the equation which in this case is y=-(7/x^2)+(6/x^3). Then equate this equation to Zero and find the value of x, the value(s) of x will the critical points of the equation. In this case critical point is x=6/7

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