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Does compiler guarantee that initializers will be executed in the same order as they appear on the initialization list?

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Does compiler guarantee that initializers will be executed in the same order as they appear on the initialization list?

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A22. No. C++ guarantees that base class subobjects and member objects will be destroyed in the opposite order from which they were constructed. This means that initializers are executed in the order, which supports the above-mentioned guarantee.

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