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Chemistry Moles. What mass of calcium carbonate must be decomposed to produce 1.4g of calcium oxide?

April 26, 2017calcium carbonate Chemistry decomposed mass Mathematics moles

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Chemistry Moles. What mass of calcium carbonate must be decomposed to produce 1.4g of calcium oxide?

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So from the balanced equation CaCO3 –> CaO+CO2 We see for 1 mole of calcium carbonate decomposed 1 mole of calcium oxide is formed So a 1:1 ratio So firstly work out the no. of moles of calcium oxide you have, n(CaO) = m/M = 1.4/ 40.08+ 16×2 = 0.02 mol Therefore 0.02 mol of Calcium carbonate would need to decompose from the 1:1 mole ratio Now rearranging the formula we can work out what mass of CaCO3 would be required mCaCO3 = n x M = 0.02 x (40.08+12.01+16×3) = 2.0 g Therefore 2.