Can someone help with Physics problems involving tension?
1. In the middle of the rope, the tension in each “half” is T/2. The upward (vertical) force is 2 * (T/2) * sin (theta) = weight (We assume the rope does not stretch and is massless) As long as Tsin(theta) > weight = m*g = 9.81 * 76.5 all is well. a) is now easy b) Use T=104*3.95 and then sind theta. I don’t have a calculator, but I have done all the physics for you. Now you need to plug-chug-think. 2) The mass of the earth is, I suppose 6E24, yes? Fearth = GM(earth) m(diver)/r^2 We don’t really need this. All we need to know is that the force of the earth attracted to the diver = the force of the diver attracted to earth = 9.81 * 53, so F = ma gives a (earth) = 9.81 * 53/6E24 which is really really small as it should be.