Assuming the radius of the sphere is 4 km, what is its density?
The sphere volume would be 2.681E11 m3. So the density would be 1957 kg/m3. Instead, assuming the density contrast is 1800 kg/m3, what is the sphere’s radius? We know that So, solving for R, we get R = 4113 m, or 4.113 km • Using the same gravity profile above, assume it is due to an infinite horizontal cylinder. Find the depth to the cylinder. Notice the the center of the anomaly is NOT at 0 km, but at 10 km. Nevertheless, the half-width of the anomaly looks to be about 7.5 km. For a cylinder, depth equals half-width, or about 7.5 km (your mileage may vary…). Find the mass excess per unit length of the cylinder, in kg/m We know where πr2ρ (or, more correctly, Dr) is the mass per unit length. Solving for this gives 1.97E10 kg/m. Assuming the radius of the cylinder is 3 km, what is its density contrast? Solve for r from above, giving a density contrast of 696 kg/m3. Instead, assuming the density contrast is 500 kg/m3, what is the cylinder’s radius? Solve for R from above, giving a rad
