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An object is 23.3 cm from the center of a silvered spherical glass Christmas tree ornament 6.50 cm in diameter. The position of the image if -1.5 cm What is the magnification of its image?

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An object is 23.3 cm from the center of a silvered spherical glass Christmas tree ornament 6.50 cm in diameter. The position of the image if -1.5 cm What is the magnification of its image?

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If the object is 23.3 cm to the center of the bulb…then that distance minus the radius of the bulb will yield the distance to the bulb dia=6.50 cm therefore r = 3.25 cm object distance (p) = 23.3 cm – 3.25 cm= 20.1 cm (sig figs) image distance (q) = -1.5 cm M = -q/p = -(-1.5cm)/(20.1cm) = .0746

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