How to solve 3 simultaneous equations?
One way to do it is to 1) Form a two equations two unknowns equation from the equations #1 and #2, and 2) Form a two equations two unknowns equation from equations #1 and #3. 1) The easiest way is to eliminate the variable “a” from #1 and #2. 440 = 8a + 472b + 480c 26860 = 472a + 28028b + 28680c Multiply the first equation by 59, to get 25960 = 472a + 27848b + 28320c 26860 = 472a + 28028b + 28680c Subtract them, -900 = -180b – 360c Which reduces as 5 = b + 2c 2) 440 = 8a + 472b + 480c 28560 = 480a + 28680b + 29700c Multiply the first equation by 60, 26400 = 480a + 28320b + 28800c 28560 = 480a + 28680b + 29700c Subtract them, -2160 = -360b – 900c -216 = -36b – 90c 12 = 2b + 5c From #1 and #2, we now have two equations and two unknowns. 5 = b + 2c 12 = 2b + 5c Solve this system of equations for b and c, and then a will be easy to get. 10 = 2b + 4c 12 = 2b + 5c 10 – 12 = 4c – 5c -2 = -c c = 2 Now that we have c, we can get b. 5 = b + 2c 5 = b + 2(2) 5 = b + 4 b = 1 Now that we have both b
